Devin Bush has earned some recognition from the NFL after a dominant performance for the Pittsburgh Steelers on Sunday.

Bush had a huge day for the Steelers in a 24-17 victory over the Los Angeles Chargers. He finished the game with seven tackles, four solo stops, a pick-six and a fumble recovery. For that effort, Bush was named the AFC Defensive Player of the Week.

Bush has played in six games as a rookie this year, and has tallied 52 total tackles, with 32 solo stops. He’s defended three passes with two interceptions. He’s also registered one sack.

Bush was a first–round selection in the 2019 NFL Draft. He’s already making a huge difference on the field for the Steelers.